• tryptaminev 🇵🇸 🇺🇦 🇪🇺@feddit.de
    link
    fedilink
    English
    arrow-up
    1
    ·
    10 months ago

    From a purely physical point of view, is that realistic?

    If all of its energy is kinetic, it means that the energy must result from it’s potential energy+any fuel it is propelled with. Ignoring air-friction and terminal velocity for free falling objects, that means that still the energy of a nuclear weapon is required to bring this thing up into space, or stored as fuel for its propulsion.

    So unless the projectile is assembled in space, any rocket bringing it into space will contain at least the energy of a nuclear warhead. Gotta be a very nervous launch, knowing that any failure will result in a fire with the energy of a nuke.

    • Brainsploosh@lemmy.world
      link
      fedilink
      English
      arrow-up
      2
      ·
      10 months ago

      A lot of the energy comes from orbital speeds.

      The Hypervelocity Rod Bundles project proposed 6,1x0,3 m tungsten rods, weighing about 8200 kg, impacting at about 3000 m/s, meaning about 42 GJ of energy per projectile [wikipedia].

      The weakest recorded nuke, the Davy Crocket Tactical Nuclear Weapon, is estimated at about twice that (84 GJ), and the largest, Tsar Bomba, at about 3 000 000x the yield (210 PJ).